问题标题:
高等数学极限lim[(x+1)/(x-2)]^(2x+1),x趋向于无穷大
问题描述:

高等数学极限lim[(x+1)/(x-2)]^(2x+1),x趋向于无穷大

童俊回答:
  lim【x→∞】[(x+1)/(x-2)]^(2x+1)   =lim【x→∞】[1-3/(x-2)]^(2x+1)   =lim【x→∞】{[1-3/(x-2)]^[-(x-2)/3]}^(-6)·[1-3/(x-2)]^5   =e^(-6)
罗宇回答:
  lim【x→∞】[(x+1)/(x-2)]^(2x+1)=lim【x→∞】[1-3/(x-2)]^(2x+1)=lim【x→∞】{[1-3/(x-2)]^[-(x-2)/3]}^(-6)·[1-3/(x-2)]^5=e^(-6)第二步1是加还是减
童俊回答:
  sorry,是加lim【x→∞】[(x+1)/(x-2)]^(2x+1)=lim【x→∞】[1+3/(x-2)]^(2x+1)=lim【x→∞】{[1+3/(x-2)]^[(x-2)/3]}^(6)·[1-3/(x-2)]^5=e^6
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